若 aaa、bbb、ccc 为整数，且 ∣a−b∣+(c−a)2024=1|a - b| + (c - a)^{2024} = 1∣a−b∣+(c−a)2024=1，则 ∣c−a∣+2∣a−b∣+3∣b−c∣=‾.|c - a| + 2|a - b| + 3|b - c| = \underline{\quad\quad}. ∣c−a∣+2∣a−b∣+3∣b−c∣=.